Electrochemistry
Galvanic
cell, EMF, Nernst Equation
Q1. Given the standard
electrode potentials: K+/K=-2.93V, Ag+/Ag=0.80V, Hg2+/Hg=0.79V,
Mg2+/Mg=-2.37V, Cr2+/Cr=-0.74V. Arrange them in their
increasing order of reducing power.
Q2. Depict the galvanic cell
in which the reaction: 2Zn + 2Ag+ → Zn2+
+ 2Ag takes place. Further show: (i) which of the electrode is negatively
charged, (ii) the carriers of the current in the cell, (iii) Individual
reaction at each electrode.
Q3. Write the Nernst
equation and the EMF of the following cells:
(i) Mg(s)|Mg2+(0.001M)||Cu2+(0.0001M)|Cu(s)
(ii) Fe(s)|Fe2+(0.001M)||H+
(1M)|H2(g)(1bar)|Pt(s)
(iii) Pt(s)|Br2(l)|Br-(0.01M)||
H+ (0.03M)|H2(g)(1bar)|Pt(s)
Given Eo Mg2+|Mg
=-2.37V, Eo Cu2+|Cu =+0.34V, Eo Fe2+|Fe
=-0.44V, E0 Br2|Br- =1.08V.
Q4. Predict if the following
reactions are feasible: (i) Fe3+(aq) and I-(aq)
(ii) Ag+(aq) and Cu (iii)
Br2(aq) and Fe2+(aq). Given: Eo Fe2+|Fe3+ =-0.774V,
E0 Br2|Br- =1.09V,
Eo Ag+/Ag =0.80V, E0
I2|I- =0.541V.
Q5. How would you determine
the standard electrode potential of Mg2+|Mg?
Q6. Can you store CuSO4
solution in a zinc pot, Eo Zn2+|Zn =-0.76V, Eo Cu2+|Cu
=+0.34V.
Q7. Calculate the potential
of hydrogen electrode in contact with a solution whose pH is 10.
Q8. Eo values :
Zn(OH)2|Zn =-1.245V, Mg(OH)2|Mg =-2.69V, Fe(OH)2|Fe
=-0.877V, Fe(OH)3|Fe =-2.3V
(i) Which is the strongest
reducing agent?
(ii) Which reducing agent
could reduce Zn(OH)2 to Zn?
(iii) Which reducing agent
could reduce Fe(OH)2 to Fe?
Q9. A zinc rod is dipped in
0.1M solution of ZnSO4. The salt is 95% dissociated at this dilution
at 298K. Calculate the electrode potential. Eo Zn2+|Zn
=+0.76V.
Q10. Represent the cell in
which the following reaction takes place: 2Mg + 2Ag+(0.0001M) → Mg2+(0.130V) +
2Ag. Calculate its Ecell if Eocell = 3.17V.
Q11. Calculate the standard
free energy change and maximum work obtainable for the reaction occurring in
Daniel cell; Zn + Cu2+ → Zn2+
+ Cu and also calculate the equilibrium constant for the reaction. Given:
Eo Zn2+|Zn =+0.76V. Eo Cu2+|Cu
=+0.34V
Q12. Estimate the minimum
potential difference needed to reduce Al2O3 at 500oC.
The standard energy change for the reaction is 960KJ. 2/3 Al2O3 →
4/3Al + O2
Q13. The cell in which the
following reaction occurs: 2Fe3+
+ 2I- → 2Fe2+ + I2 has Eocell
= 0.236V Calculate gibbs free energy change and equilibrium constant of the
cell reaction.
Q14. 0.05M NaOH solution offered a resistance of
31.6 Ω in a conductivity cell at 298K. If the cell constant of the cell is
0.367 cm-1, calculate molar conductivity of the solution. [232 Ω-1cm2mol-1]
Q15. The resistance of semimolar solution of an
electrolyte enclosed between two platinum electrodes 1.5 cm apart and having an
area of 2 cm2 was found to be 30 Ω. Calculate the molar conductance
of the solution. [50 Ω-1cm2mol-1]
Q16. The specific
conductance of a 0.01M solution of acetic acid at 298k is 1.65 X 10-4
Ω-1 cm-1. Calculate: (i) molar conductance of the
solution, (ii) degree of dissociation of acetic acid, (iii) dissociation
constant. [Given: Λ0(H+) =349.1 and Λ0(CH3COO-)
=40.9 Ω-1cm2mol-1]
Q17. The molar conductance
at infinite dilution for NH4Cl, NaOH and NaCl are 129.8, 217.4 and
108 Ω-1cm2mol-1 respectively. If molar
conductance of 0.01M solution of NH4OH is 9.33 Ω-1cm2mol-1.
Calculate (i) molar conductance at infinite dilution, (ii) degree of
dissociation of NH4OH.
Q18. The Λ0 values of KNO3 and LiNO3
are 145 and 110.1 Ω-1cm2mol-1 respectively.
The Λ0 value for K+ ion is 73.5 Ω-1cm2mol-1.Calculate
Λ0(Li+). [38.6 Ω-1cm2mol-1]
Q19. Calculate the number of
coulombs required to deposit 6.75g of Al from AlCl3.
Q20. An aqueous solution of
an unknown salt of Palladium is electrolysed by a current of 3 A passing for 1
hour. What is the charge of palladium ions in solution if 2.977g of Pd ions are
reduced at cathode? [+4]
Q21. Calculate the e.m.f. of
the cell: Cr(s)|Cr3+(0.1M)||Fe2+(0.01M)|Fe(s). Given: Eo Cr3+|Cr = - 0.75V, Eo Fe2+|Fe = - 0.45 V.
Q22. Calculate standard electrode potential of Ni2+/Ni
if the cell potential of the cell:
Ni(s)|Ni2+(0.01M)||Cu2+(0.1M)|Cu(s) is 0.59V.
Given: Cu2+/Cu = 0.34V.
[- 0.2205 V]
Q23. For the cell, Mg(s)|Mg2+(aq)||Ag+(aq)|Ag(s),
calculate the equilibrium constant at 250C and also the maximum work
that can be obtained by operating the cell. Eo
( Mg2+|Mg) = - 2.37V, Eo (Ag+|Ag) =
+ 0.80 V.
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