d-
and f- block elements
d-block elements
represent change in properties from most electropositive s-block elements to
least electropositive p-block elements. So, these are called transition metals.
Transition elements are those
elements which have partially filled d-subshells in their elementary state or
in their commonly occurring oxidation states.
General configuration =
(n-1) d1-10 ns1-2
There are four transition series:
3d – Sc Ti V Cr
Mn Fe Co Ni Cu Zn
4d – Y Zr
Nb Mo Tc Ru
Rh Pd Ag Cd
5d – La Hf Ta W Re
Os Ir
Pt Au Hg
6d – Ac Ku
Ha
Cu = 3d10 4s1. But in its most common oxidation
state (+2), it contains one unpaired electron in its d-orbital. So, it is a
transition element. Cu2+ = 3d9 4s0. Similarly,
Ag and Au are also transition elements.
Physical Properties
–
1) Atomic radii
– Across the period (series), atomic radii of elements of a particular series
decrease with increase in atomic number and then become constant in mid-way and at last, there
is an increase in atomic radius.
Reason – With increase in atomic
number, nuclear charge goes on increasing and force of attraction between
nucleus and valence electrons increases due to which atomic radius decreases
with increase in atomic number in the beginning.
But as the electrons are
increased in d-orbitals. These electrons screen the outermost s-electrons. So,
as the d-electrons increase, screening effect increases which neutralises the
effect of increased nuclear charge and hence, atomic radius remains almost
unchanged after chromium.
At the end of the series, there
is slight increase in the atomic radii due to increased electron-electron
repulsions between electrons in same orbitals due to which electron cloud
expands and size increases.
Down the group, atomic radii
increase due to increase in number of shells. But atomic radii of elements of
4d-series and 5d-series are nearly same due to Lanthanide Contraction.
2) Metallic character
- All transition elements are metals. They have high density, hardness, high
melting point and boiling point, malleable, ductile, conduct electricity and
heat.
Reason – Metallic character is
due to their low ionization energies and number of vacant orbitals in outermost
shell. Greater the number of unpaired d-electrons, greater is the number of
bonds and greater is the strength of metallic bonds. E.g. Cr, Mo and W
(tungsten) have maximum number of unpaired electrons and are very hard metals.
Zn, Cd and Hg do not have any unpaired electrons. So, they are not hard
(nd10). They are also known as non-transition metals.
3) Density –
All metals have high density. Osmium has the highest density.
4) Melting point and
boiling point – They have high melting point and boiling point due
to strong metallic bonds between atoms of elements.
Metallic bond is formed due to
the interaction of electrons in outermost orbitals. Greater the number of
valence electrons, stronger is the metallic bonding and higher is the melting
point. In a particular series, metallic strength increases upto middle with
increasing availability of unpaired electrons upto d5 configuration
(Sc =1, Ti =2, V =3, Cr =4, Mn =5) and then decreases with decreasing
availability of unpaired electrons in d-orbital. Therefore, melting point
decreases.
5) Ionization enthalpy –
Energy required to remove an electron from valence shell of an isolated gaseous
atom. First ionization enthalpy is higher than those of s-block elements and
lesser than p-block elements.
Reason – Due to increase in
nuclear charge and force of attraction between nucleus and valence electrons.
Hence more energy is required to remove an electron from outermost shell.
Also, the effect of increasing
nuclear charge is opposed by additional screening effect of nucleus and hence,
ionization enthalpy increases but quite slowly among d-block series.
First ionization enthalpy of 5-d
series is higher than those of 3d- and 4d- series due to poor shielding effect
of 4f-orbitals. As a result, outer electrons have greater nuclear charge acting
on outer valence electrons.
Consequences: a) Ni (II)
compounds are thermodynamically more stable than Pt(II) compounds. Pt(IV)
compounds are more stable than Ni(IV) compounds. E.g. K2PtCl6
exist but not K2NiCl6.
6) Oxidation state
– Transition metals exhibit variable oxidation states.
Reason- This is due to the
participation of inner (n-1) d-electrons in addition to outer n electrons
because energies of ns- and (n-1) d subshells are almost equal. They contain
many unpaired electrons.
Highest oxidation state is shown
by Osmium(Os) and Rhuthenium(Ru) of +8.
Few transition metals also form
compounds in low oxidation states like +1, 0, -1. E.g. [Ni(CO)4],
[Fe(CO)5] in which Ni and Fe have zero oxidation states.
7) Formation of coloured
ions – s and p-block elements are white in colour while d-block
elements are coloured in solid or solution form.
Reason- It occurs due to the
presence of unpaired electrons. The energies of five d-orbitals in the same
subshell do not remain equal during the formation of complexes or compounds of
transition metals. Under the influence of approaching ions towards the central
metal ion, d-orbitals split into different energy levels. This phenomenon is
known as crystal field splitting (CFS).
In case of transition metal ions,
electrons are excited from one energy level to another in same d-subshell.
These are known as d-d transitions. The amount of energy required to excite
unpaired electrons to higher excited states within the same d-subshell
corresponds to energy of certain colours of visible light and the observed
colour of substance is always complementary colour of colour absorbed by the
substance.
Zn, Cd and Hg compounds are generally white in colour because of
completely filled d-orbitals i.e. they do not have any unpaired electron (d10).
8) Magnetic properties
– Most of the compounds of transition elements are paramagnetic due to the
presence of unpaired electrons in the d-orbitals of metal ion. Unit of magnetic
moment (μ)
= Bohr Magneton. μ = n ( n + 2 ) where n = number of unpaired electrons
Iron oxide = Ferromagnetic substance
(highly magnetic).
Zn2+, Cd2+, Hg2+,
Cu+ compounds = Diamagnetic (no unpaired electron).
9) Tendency to form complexes –
Transition elements form large number of coordination compounds. The transition
metal ions bind to number of anions or neutral molecules (ligands) in the
complexes like [Ni(NH3)6]2+, [Co(NH3)6]3+,
etc.
Reason- due to small size of
transition metal atoms or ions, high nuclear charge, presence of vacant
d-orbitals of suitable energy are available to accept lone pair of electrons
donated by ligands.
10) Formation of interstitial compounds –
Transition metals form interstitial compounds with elements like B, C and N
i.e. they get trapped in vacant spaces of lattices of these metals.
Reason- Transition metals can easily accommodate the
vacant spaces of these non-metals due to their small size, defects in
structures and their variable oxidation states.
11) Catalytic properties – Many
transition metals and their compounds act as good catalyst for many reactions
like Ni, Pt, Pd, V2O5, MnO2, etc.
Reason- (i) due to the presence of
vacant orbitals and their tendency to show variable oxidation states, (ii)
Transition metals provide large surface area on which reactants may be absorbed
for the reaction to occur. E.g. in Contact process, solid V2O5
adsorbs SO2 for reaction.
12) Alloy formation -
Transition metals form large number of alloys.
Reason- Transition metals are quite
similar in size and atoms of one element in its crystal lattice substitute
atoms of other metal in its crystal lattice. E.g. Brass = Cu + Zn, Bronze = Cu
+ Sn, Stainless steel = Fe + Cr + Ni (high melting point, hard, more resistant
to corrosion).
13) First row transition metals –
Oxides- General formulae: MO, M2O3, M3O4,
MO2, M2O5, MO3 .
Acidic character increases as
oxidation state increases.
Oxide : MnO Mn2O3 Mn3O4 MnO2 Mn2O7
Oxidation: +2 +3 +8/3 +4 +7
Reducing character of
oxides –Across the period, reducing character first increases then
decreases as oxidation state. Lower oxidation state is more stable in 3d-series
i.e. +2 state. V2O5 and CrO are strong reducing agents.
As we move down the group, higher oxidation
states become more stable. E.g. Osmium(VIII) oxide (OsO4) is known
but iron (VIII) oxide is not known. Similarly, hexafluorides of 4d- and 5d-series
exist.
K2Cr2O7 (potassium dichromate):
Preparation: from chromite ore
(i) 4FeCr2O4
+ 16NaOH + 7O2 → 8Na2CrO4 + 2 Fe2O3
+ 8H2O
(ii) 2Na2CrO4
+ H2SO4 → Na2Cr2O7 + Na2SO4 + H2O. Na2SO4 can be removed
by crystallization.
(iii) Na2Cr2O7 + 2KCl → K2Cr2O7 + 2NaCl. So, orange crystals of K2Cr2O7 are obtained.
Properties: (i) It is orange red crystalline solid, soluble in
water.
(ii) Action of heat: 4 K2Cr2O7 → 4
K2Cr2O4 + 2 Cr2O3 + 3O2
(iii) K2Cr2O7 + 2 KOH → 2 K2Cr2O4
+ H2O
2 K2CrO4 +
H2SO4 → K2Cr2O7 + K2SO4 + H2O
(iv) Chromyl chloride test – used
to test the presence of chloride ions.
K2Cr2O7
+ 4NaCl + 6H2SO4 → 2KHSO4 + 4NaHSO4
+ 3H2O + 2Cr2O2Cl2 (chromyl
chloride red vapours)
(v) K2Cr2O7
+ 4HCl →
2KCl + 2CrCl3 + 7H2O + 3Cl2
(vi) Oxidising character- K2Cr2O7
is a powerful oxidizing agent.
K2Cr2O7
+ 4H2SO4 → K2SO4 + Cr2(SO4)3
+ 4H2O + 3[O]
Strong oxidizing agent in acidic
medium:
Cr2O72-
+ 14 H+ + 6e- → 2Cr3+ (green) + 7
H2O
Uses: a) in volumetric analysis of Fe2+, I-. b) in photography for hardening gelatin
film. c) in dyeing.
Note: a) 2I- → I2
+ 2e- b) Fe2+
→
Fe3+ + e- c) H2S → S
+ 2H+ + 2e-
d) H2C2O4
→
2CO2 + 2H+ + 2e- e) SO32-
+ H2O → SO42- +
2e- + 2H+
KMnO4 =
Potassium permanganate
Preparation: 1) a) 2MnO2 + 4KOH + O2 →2K2MnO4
+ 2H2O
b) 3MnO42-
+ 4H+ → 2MnO4- + MnO2 + 2H2O [Disproportionation reaction]
2) Commercial process: KMnO4 is prepared by the alkaline
oxidative fusion of MnO2 followed by electrolytic oxidation of
manganite (VI)
Properties: a) It is dark violet crystalline solid.
b) It is fairly soluble in water.
c) 2KMnO4 K2MnO4 +
MnO2 + O2
d) 4KMnO4 + 4KOH → 4K2MnO4
+ 2H2O + O2
e) It is powerful oxidising agent in
neutral, alkaline or acidic solutions. MnO4- + e- → MnO42-,
MnO4- + 4H+
+3e- → MnO2 + 2H2O, MnO4- +
8H+ +5e- → Mn2+
+ 4H2O.
Uses: as an
oxidizing agent in labs and industries, used as disinfectant for water, in quantitative
and qualitative analysis.
E0 values (standard
electrode potential) become less negative across the series is related to the
general increase in sum of the first and second ionization enthalpies.
More the ionization enthalpy is, more
is the reduction potential and lesser is the oxidation potential. So, E0
value (reduction potential) becomes more negative.
Exception: a) E0
for Mn, Ni and more (-) than expected from the trend. This is due to the
stability of the half-filled d subshell in Mn2+ and completely
filled d10 configuration in Zn2+, whereas E0
for Ni is related to the highest negative ΔhydH0
(hydration energy).
b) Cu2+ = 3d9 4s0, Cu+ = 3d10
4s0
Cu2+
is exceptionally more stable than Cu+ in aqueous solutions
because of more negative ΔhydH0 of Cu2+ (aq)
than Cu+ , which is more than compensates for the second ionization
enthalpy of Cu. So, Cu+ undergoes disproportionation in aqueous
solution. 2 Cu+ (aq) → Cu2+ + Cu. E0 = + 0.34V
(favourable E0 value).
c) All Cu2+ halides are
known except the iodide. In this case, Cu2+ oxidises I- to I2.
2 Cu2+ + 4 I- →
Cu2I2 (s) + I2
Stable d-configurations – d3
= stable half-filled t2g configuration, d5 = half-filled
d-orbital, d6 = fully-filled t2g level, d10 =
fully-filled d-orbital.
f-block elements: Elements
in which last electron enters the f-orbital of their atoms are called f-block
elements. They are known as inner transition elements.
General Configuration: (n-2)f1-14
(n-1)d0-10 ns1-2
(n-2) = Anti-penultimate shell,
(n-1) = Penultimate shell, n =
main ( valence ) shell.
They consist of two series of elements
placed at the bottom of periodic table by filling of electrons in 4f- and
5f-orbitals.
(i) Lanthanoids or lanthanides- The series involving the filling of
4f-orbitals following Lanthanum (Z=57), Cerium (Z=58) to Lutetium (Z=71).
They occur very rarely and are known
as rare earth metals.
Z=57 = La (Lanthanum) = 5d1
6s2, Z=58 = Ce (Cerium) =
4f1 5d1 6s2, Z=59 = Pr (Praseodymium) = 4f2 6s2, Z=63 = Eu (Europium) = 4f7 6s2 , Z=64 = Gd (Gadolinium) = 4f7 5d1 6s2, Z=71 = Lu
(Lutetium) = 4f14 5d1
6s2.
(ii) Actinides - The
series involving the filling of 5f-orbitals following Actinium (Z=89), Thorium
(Z=90) to Lawrencium (Z=103).
Actinium (Z=89) = Ac = 6d1
7s2, Thorium (Z=90) = Th = 6d2
7s2, Curium (Z=96) = Cm = 5f7 6d1 7s2,
Lawrencium (Z=103) = Lr = 5f14 6d1 7s2
The Lanthanoids- All
Lanthanoids have common oxidation state of +3 with +2 and +4 also by attaining
stable f0, f7, f14 configurations.
Physical
Properties: All lanthanides are soft, malleable, and ductile with low
tensile strength, bad conductors of heat and electricity.
General
Charcteristics: 1)
Trivalent ions of lanthanides are coloured in solid state as well as in
solution due to the absorption in visible light of spectrum by unpaired
electrons resulting in f-f transitions.
2) They are paramagnetic. All
lanthanides are highly electropositive metals and have almost similar
reactivity due to the fact that lanthanides differ only in number of 4f
electrons. Since these electrons are very effectively shielded from interaction
by 6s, 5p electrons, hence they show little differences in their chemical
reactivity. So, they are difficult to separate.
f0 and f14 are
colourless and diamagnetic [La3+ and Lu3+]
3) Atomic radii- The steady decrease
in atomic sizes and ionic sizes of lanthanides with increasing atomic number is
known as lanthanide
contraction.
Reason: As atomic number increases
across the series, nuclear charge increases by one unit. The new electrons are
added to same inner 4f-subshells. But 4f electrons shield each other from
nuclear charge quite poorly because of very diffused shapes of f-orbitals.
Consequences of lanthanide
contraction:
a) Elements of 4f- and 5f- transition
series resemble each other due to similar sizes.
b) It is difficult to separate these
elements in pure state. Fractional crystallization method is done repeatedly to
separate them.
c) Due to lanthanide contraction, size
of lanthanide ions decrease with increase in atomic number due to which the
covalent character between Lanthanide ion and OH- ions increase from
La3+ to Lu3+. Therefore, basic strength of hydroxides
decreases with increase in atomic number across the series. Thus, La(OH)3
is most basic and Lu(OH)3 is least basic.
The actinoids-
General Characteristics: 1) These
metals are all silvery in appearance.
2)Antinoid contraction- The
steady decrease in atomic sizes and ionic sizes of antinoids with increasing
atomic number is known as actinide contraction.
Reason: As atomic number increases
across the series, nuclear charge increases by one unit. The new electrons are
added to same inner 5f-subshells. But 5f electrons shield each other from
nuclear charge quite poorly.
3) They are radioactive elements and
earlier members have relatively long half lives, the latter ones have half
lives ranging from a day to 3 minutes for Lawrencium (Z=103). The latter
members are prepared only in nanogram quantities. These facts render their
study more difficult.
Lanthanoids
|
Actinoids
|
1) Tendency to form complexes is less.
|
1) More tendency to form complexes.
|
2) Non-radioactive except promethium.
|
2) All are radioactive.
|
3) All show +3 oxidation state and few show
+2 and +4 also.
|
3) All show +3, +4, +5, +6 and +7 oxidation
state.
|
4) They are less basic.
|
4) They are more basic.
|
Misch Metall- An alloy
of a lanthanoid metal (95%) and iron (5%) with traces of S, C, Ca and Al. It is
used in Mg-based alloy to produce bullets, shell and lighter flint.
Uses
of Lanthanoids: (i) For production of alloy steels for plates and pipes. (ii)
Mixed oxides of lanthanoids are used as catalysts in petroleum cracking.
Reactions
of Lanthanoids:
2Ln + 3X2 → 2LnX3
, 2Ln + 6H2O → 2Ln(OH)3 + 3H2 ,
Ln + O2 → Ln2O3
, Ln + S →Ln2S3 , Ln + N2 → LnN, Ln + C → LnC2
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