THERMODYNAMICS
It is the branch of chemistry which
deals with energy changes in the chemical reactions and their feasibility.
System
– Part
of universe in which observations are made.
Surroundings
- Part of universe excluding system = Universe –
System
Types
of System –
a) Open
System - There is exchange of energy
and matter between system and surroundings. e.g. Open beaker.
b) Closed
system - There is no exchange of
matter but exchange of energy is possible between system and surroundings. e.g.
presence of reactants in a closed vessel made up of conducting material.
c) Isolated
system - There is no exchange of
energy as well as matter between system and surroundings. e.g. Presence of
reactants ina thermos flask or any insulated closed vessel.
State
of the system - The system must be described in order to make
useful calculations by specifying quantitatively each of the properties such as
pressure (P), volume (V) and temperature (T) as well as the composition of the
system.
The state of the system is described
by its measurable or macroscopic (bulk) properties.
State
functions or state variables - Those properties of a system which depend only
on the state (initial and final state) of the system and do not depend upon the
path of the system e.g. P.V.T.
Path
functions - Those properties of a system which do not
depend upon the state (initial and final state) of the system but depend only
upon the path of the system e.g. work done.
Types
of processes :
a) Isothermal
process – that occurs at constant temperature.
b) Isobaric
process – that occurs at constant pressure
c) Isochoric
process – that occurs at constant volume
d) Adiabatic process – that occurs at constant heat i.e.,
there is no heat exchange between system and surroundings.
Internal
energy (U or E) - It is the energy possessed by the system. It
depends upon –
a) Heat
passes into or out of the system
b) Work
is done on or by the system
c) Matter
enters or leaves the system
Internal energy is a state function
as it depends upon initial and final state of the system
We cannot calculate the exact value
of internal energy as it is the sum of many different kinds of energy such as
mechanical energy, chemical energy, electrical energy, etc. whose values are
difficult to calculate separately.
For adiabatic process, ΔU = U2
– U1 = Wad
FIRST
LAW OF THERMODYNAMICS –
- According to it,
energy of an isolated system is constant
- Energy
can neither be created nor be destroyed
Mathematically, ΔU = q + w
Where U = change in internal
energy, q = heat absorbed by the system, W = work done on the system.
Proof – Let
initial internal energy = U1, final internal energy = U2.
If ‘W’ work is done on the system and ‘q’ heat is absorbed. Then,
U2
= U1 + q + W
U2
– U1 = q + W
ΔU
= q + W
Sign
Conventions –
Work
done by the system = (.), Work done
on the system = (+)
Heat
absorbed → q = (+) and U = (+), Heat
evolved → q = (–) and U = (–)
During
expansion W = (–). During compression W = (+)
For
adiabatic process, ΔU = – Wad
For
thermally conducting process, ΔU = – q
For
closed system, ΔU = q + w
If
the work is done by the system, ΔU = q – W
→ ΔU = q – W
APPLICATIONS
:
1. Work – (I
= length, A = area) For 1 mole of a gas
Change in volume V = 1 × A
As
P = Force / area
→
F on piston = Pext . A
Work
done = F × distance = P × A × I = P × (–ΔV). Therefore, W = – P Δ V
2.
W
= – 2.303 nRT log V2 / V1
Also, As Boyle’s law : P1/P2
= V2/V1
→
W = – 2.303 nRT log P1/P2
Now
cases :
a) For
isothermal process (T = constant) i.e., for isothermal expansion of ideal gas
into vacuum,
W
= 0 and q = 0 → ΔU = 0
b) For
isothermal irreversible change, q = W = P (V2 – V1)
c) For
isothermal reversible change, q = – W = nRT InV2 / V1
d) For
adiabatic change, q = 0 → ΔU = Wad
Enthalpy
(H) :
It is the heat absorbed or heat
evolved by the system.
As U = qp – P Δ V
(expansion)
qp
= ΔH = ΔU + P Δ V
Proof
: ΔU = q – PΔV
U2 – U1 = qP
– P (V2 – V1) at constant P
qp = (U2 + PV2)
– (U1 + PV1)
Therefore, H = U + PV
qp = H2 – H1
= ΔH ( it is also known as state function)
Now, if H = U + PV
ΔH = ΔU + ΔpV + pΔV
As H = qp (at constant
Pressure) i.e. ΔP = 0
Therefore,
ΔH = ΔU + PΔV
ΔH = (+) for endothermic reaction,
ΔH = (.) for exothermic reaction.
Derivation
ΔH = ΔU + ΔngRT
Proof ΔH = ΔU + PΔV = ΔU + P (V2 – V1)
Now,
if PV = nRT. So, PV1 = n1RT and PV2 = n2RT
ΔH
= ΔU + n2RT – n1RT = ΔU + (n2 – n1)
RT
ΔH
= ΔU + ΔngRT
Where
Δng = n2 – n1 for gaseous state = np – nr
– Extensive Property – Property
whose value depends upon the quantity of matter contained in the system. e.g.
mass, volume, internal energy, enthalapy, heat capacity. etc.
– Intensive
Property - Property whose value does
not depend on the quantity or size of matter present in the system. e.g.
temperature, density, pressure
– Heat
Capacity (C) – It is the amount of heat required to raise the temperature
of a substance by IC.
Specific
Heat Capacity (CS) –Amount
of heat required to raise the temperature of 1gram of a substance by 1°C (1K).
Molar Heat Capacity (Cm) –Amount
of heat required to raise the temperature of 1 mole of a substance by 1°C.
Q
= m C ΔT where ΔT = T2 –
T1
Relationship
between CP and CV for ideal gases –
For
constant volume, qV = CVΔT = ΔU and at
constant P, qP = CPΔT = ΔH
For
1 mole of a gas, ΔH = ΔU + R ΔT
On
putting the values of ΔH and ΔU, we get
CPΔT = CVΔT + R ΔT
VP
= VC + R Therefore, CP – CV = R
We can measure energy changes (ΔH
and ΔU) associated with chemical or physical processes by an experimental
technique called calorimetry. The process is carried out in calorimeter
immersed in a known volume of a liquid.
Knowing that heat capacity of
liquid in which calorimeter is immersed and heat capacity of calorimeter, it is
possible to determine the heat evolved in the process of measuring temperature
changes under two different values, a)
at constant volume, b) at constant
pressure.
ΔH
= HP – HR
Enthalpy
changes - Reactants →
Products
The enthalpy changes accompanying
the reaction is known as reaction enthalpy (ΔH)
Standard
enthalpy of reaction - The reaction enthalpy changes for a
reaction when all the participating substances are in their standard states
[standard temperature and pressure (1 bar) [Δ,H0]
DEFINITIONS
1. Standard enthalpy of fusion (ΔfusH0) - It is the heat evolved or absorbed by the
system when one mole of a solid substance melts in standard state.
2. Standard enthalpy of vapourisation (vapH0)
- Amount of heat require to vapourize mole of a
liquid at constant temperature and under standard pressure (1 bar)
3. Standard enthalpy of sublimation (ΔsubH0) - Amount of heat absorbed or evolved when
sublimes at constant temperature and standard pressure (1 bar)
ΔH is directly
proportionsal to the intermolecular interactions in substance
4. Standard enthalpy of formation (ΔtH0) - Amount of heat absorbed or evolved when 1 mole
of compound is formed from its elements in their most stable states (reference
state) at 25°C and 1 bar.
Example
- H2
(g) + 1/2O2 (g) → H2O (1) ΔtH0 =
285.8KJ/mol; C (graphite) + 2H2 (g) → CH4 (g)
5. Standard
enthalpy of combustion – (ΔCH0)
Enthalpy change when 1 mole of a substance is burnt in presence of air
completely.
6. Enthalpy of atomization (ΔaH0) – It is enthalpy
change on breaking 1 mole of bonds completely to obtain atoms in the gas phase.
Example
- CH4 (g) → C
(g) + 4H (g) Na (s) → Na
(g)
7. Bond
enthalpy (ΔbondH0) - Energy is required break a
bond and released to form a bond.
The amount of
heat absorbed or released due to break or form one mole of bonds of reactants
is known as bond enthalpy. ΔrH0
= BER – BEP
8. Enthalpy of solution (ΔsolH0) – It is
the enthalpy change when 1 mole of a substance is dissolved in specified amount
of solvent.
9. Lattice enthalpy – It
is the enthalpy change which occurs when 1 mole of an ionic compound
dissociates into its ios in gaseous state (ΔLattice H or U)
10. Heat
of hydration - Amount of enthalpy
change when 1 mole of the anhydrous salt combines with required number of moles
of water so as to change into the hydrated salt. CuSO4 + aq → CuSO4.5H2O
11. Heat of neutralization of an acid by a
base - It is the heat
change when 1 gram equivalent of the acid is neutralized by a base, the
reaction is carried out in dilute aqueous solution.
When 1 gram equivalent of HCI is neutralized by NaOH or
vice-versa, 57.1 kJ of heat is produced
– Heat of neutralization is taken for 1
gram equivalent of acid and base because neutralization involves combination of
1 mole of H+ ions with 1 mole of –OH ions. 1 gram of any
acid on complete dissociation gives 1 mole of H+ ions but 1 mole of
an acid may not give 1 mole of H+ ions.
Example
- 1 mole H2SO4 → 2 moles
of H+ ions on complete dissociation,
1 gram
equivalent H2SO4 →
1 mole of H+ ion
Hess’s
law of constant heat summiation –
According
to it, if a reaction takes place in several steps then its standard enthalpy is
the sum of the standard enthalpies of the intermediate reaction into which the
overall reaction may be divided at same temperature. OR
According
to it, if a reaction takes place in one step or in many number of steps, the
amount of energy released or absorbed (enthalpy change) always remain constant
at constant temperature.
Example
- C
(graphite, s) + O2 (g) → CO2
Step 1 : C (s) + ½ O2 →
CO (g); Step 2 : CO (g) + ½ O2 → CO2 (g) i.e. ΔH = H1 + H2
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